8j^2-j-8=0

Solution for 8j^2-j-8=0 equation:

8j^2-j-8=0

We add all the numbers together, and all the variables

8j^2-1j-8=0

a = 8; b = -1; c = -8;
Δ = b2-4ac
Δ = -12-4·8·(-8)
Δ = 257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{257}}{2*8}=\frac{1-\sqrt{257}}{16}
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{257}}{2*8}=\frac{1+\sqrt{257}}{16}
$